Optimal. Leaf size=154 \[ \frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^4 d}+\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}-\frac{b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 a^4 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d} \]
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Rubi [A] time = 0.445549, antiderivative size = 154, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {2725, 3055, 3001, 3770, 2660, 618, 204} \[ \frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^4 d}+\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}-\frac{b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 a^4 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d} \]
Antiderivative was successfully verified.
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Rule 2725
Rule 3055
Rule 3001
Rule 3770
Rule 2660
Rule 618
Rule 204
Rubi steps
\begin{align*} \int \frac{\cot ^4(c+d x)}{a+b \sin (c+d x)} \, dx &=\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d}-\frac{\int \frac{\csc ^2(c+d x) \left (2 \left (4 a^2-3 b^2\right )-a b \sin (c+d x)-3 \left (2 a^2-b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{6 a^2}\\ &=\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d}-\frac{\int \frac{\csc (c+d x) \left (-3 b \left (3 a^2-2 b^2\right )-3 a \left (2 a^2-b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)} \, dx}{6 a^3}\\ &=\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d}+\frac{\left (b \left (3 a^2-2 b^2\right )\right ) \int \csc (c+d x) \, dx}{2 a^4}+\frac{\left (a^2-b^2\right )^2 \int \frac{1}{a+b \sin (c+d x)} \, dx}{a^4}\\ &=-\frac{b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 a^4 d}+\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d}+\frac{\left (2 \left (a^2-b^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^4 d}\\ &=-\frac{b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 a^4 d}+\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d}-\frac{\left (4 \left (a^2-b^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^4 d}\\ &=\frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{a^4 d}-\frac{b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 a^4 d}+\frac{\left (4 a^2-3 b^2\right ) \cot (c+d x)}{3 a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^2(c+d x)}{3 a d}\\ \end{align*}
Mathematica [B] time = 6.12535, size = 350, normalized size = 2.27 \[ \frac{\left (3 a^2 b-2 b^3\right ) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )}{2 a^4 d}+\frac{\left (2 b^3-3 a^2 b\right ) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )}{2 a^4 d}+\frac{\csc \left (\frac{1}{2} (c+d x)\right ) \left (4 a^2 \cos \left (\frac{1}{2} (c+d x)\right )-3 b^2 \cos \left (\frac{1}{2} (c+d x)\right )\right )}{6 a^3 d}+\frac{\sec \left (\frac{1}{2} (c+d x)\right ) \left (3 b^2 \sin \left (\frac{1}{2} (c+d x)\right )-4 a^2 \sin \left (\frac{1}{2} (c+d x)\right )\right )}{6 a^3 d}+\frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{\sec \left (\frac{1}{2} (c+d x)\right ) \left (a \sin \left (\frac{1}{2} (c+d x)\right )+b \cos \left (\frac{1}{2} (c+d x)\right )\right )}{\sqrt{a^2-b^2}}\right )}{a^4 d}+\frac{b \csc ^2\left (\frac{1}{2} (c+d x)\right )}{8 a^2 d}-\frac{b \sec ^2\left (\frac{1}{2} (c+d x)\right )}{8 a^2 d}-\frac{\cot \left (\frac{1}{2} (c+d x)\right ) \csc ^2\left (\frac{1}{2} (c+d x)\right )}{24 a d}+\frac{\tan \left (\frac{1}{2} (c+d x)\right ) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{24 a d} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.121, size = 348, normalized size = 2.3 \begin{align*}{\frac{1}{24\,da} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}-{\frac{b}{8\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}}-{\frac{5}{8\,da}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{{b}^{2}}{2\,d{a}^{3}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }+2\,{\frac{1}{d\sqrt{{a}^{2}-{b}^{2}}}\arctan \left ( 1/2\,{\frac{2\,a\tan \left ( 1/2\,dx+c/2 \right ) +2\,b}{\sqrt{{a}^{2}-{b}^{2}}}} \right ) }-4\,{\frac{{b}^{2}}{d{a}^{2}\sqrt{{a}^{2}-{b}^{2}}}\arctan \left ( 1/2\,{\frac{2\,a\tan \left ( 1/2\,dx+c/2 \right ) +2\,b}{\sqrt{{a}^{2}-{b}^{2}}}} \right ) }+2\,{\frac{{b}^{4}}{d{a}^{4}\sqrt{{a}^{2}-{b}^{2}}}\arctan \left ( 1/2\,{\frac{2\,a\tan \left ( 1/2\,dx+c/2 \right ) +2\,b}{\sqrt{{a}^{2}-{b}^{2}}}} \right ) }-{\frac{1}{24\,da} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-3}}+{\frac{5}{8\,da} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}}-{\frac{{b}^{2}}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}}+{\frac{b}{8\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-2}}+{\frac{3\,b}{2\,d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) }-{\frac{{b}^{3}}{d{a}^{4}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.50799, size = 1507, normalized size = 9.79 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.20701, size = 369, normalized size = 2.4 \begin{align*} \frac{\frac{a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 3 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 15 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 12 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{3}} + \frac{12 \,{\left (3 \, a^{2} b - 2 \, b^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right )}{a^{4}} + \frac{48 \,{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )}{\left (\pi \left \lfloor \frac{d x + c}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (a\right ) + \arctan \left (\frac{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + b}{\sqrt{a^{2} - b^{2}}}\right )\right )}}{\sqrt{a^{2} - b^{2}} a^{4}} - \frac{66 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 44 \, b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 15 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 12 \, a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 3 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a^{3}}{a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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